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st: multiple CI/mean plots in one graphic
From
"Pieter-Jan" <[email protected]>
To
<[email protected]>
Subject
st: multiple CI/mean plots in one graphic
Date
Thu, 28 Apr 2011 19:33:23 +0200
Dear Statalisters,
Recently we performed a randomized crossover study in which we monitored the
lung function of a group of volunteers during three days. Day 1 was used to
determine baseline lung function whereas day 2 and 3 were used to monitor
lung function after inhaling either placebo (air) or active gas (oxygen)
under hyperbaric condition. During each measurement day lung function was
measured 6 times. All variables and observations were put in a dataset which
initially had the following format:
ID Group Time Variable1 etc
1 0 0 6.19
2 0 0 5.97
Etc
ID exist of 13 persons
Group: 0 (baseline), 1 (placebo), 2 (active)
Time: 0, 2, 4, 8, 12, 22 hours after exposure
To give the reader a good overview how f.e. variable 1 changes over time
within the 3 groups I want to plot the CI and mean of each group on each
time point in one graphic. I tried civplot
Civplot variable1, by(time)
But that gives me no separate plots of the three groups.
I tried to change the dataset by deleting the group variable and changing
the Variable1 etc as follows
ID Time Variable1_baseline Variable1_placebo
Variable1_active etc
1 0 6.19 6.01
6.11
2 0 5.97 6.05
5.91
Civplot variable1_baseline, by(time)
This allows me only 1 civplot for each variable but just like the first
attempt this gave me only 1 plot per graphic. I tried also twoway
Twoway (scatter variable1_baseline time) (fpfit variable1_baseline time)
(scatter variable1_placebo time) (fpfit variable1_placebo time) (scatter
variable1_active time) (fpfit variable1_active time)
And this gives the possibilities of putting multiple plots in one graphic
but specially the scatter makes it cluttered. A simple CI/mean would
counteract this.
Is there a possibility in Stata of putting multiple CI/mean plots into one
graphic? Maybe the answer speaks for itself but I am rather new into Stata
that's why I asking this question.
Many thanks,
Pieter-Jan van Ooij
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