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st: Re: question about ids in a group
From
"Joseph Coveney" <[email protected]>
To
<[email protected]>
Subject
st: Re: question about ids in a group
Date
Sun, 20 Mar 2011 12:33:29 +0900
Pat R wrote:
I have a panel dataset from which I'm trying to make a smaller dataset
with new identifiers. My (new) dataset is organised this way right
now:
QID | Year | PersonID
1 | 2009 | 3
1 | 2009 | 4
2 | 2009 | 9
2 | 2009 | 10
2 | 2010 | 9
2 | 2010 | 10
2 | 2009 | 11
I want to create new identifiers for each person (consistent across
years), starting from 1, within each QID. I tried using the -egen
group- function, but since I cannot combine that with -by-, it creates
unique values which ignore the QID. I tried using -egen rank-, but
that of course skips a rank if two IDs are the same. I'm sure there's
a terribly easy way to do this, but I just can't see it. Can anyone
help? (It's my first time asking a question, so I apologize if I've
left out important information)
--------------------------------------------------------------------------------
If I understand you correctly, then it would be something like that illustrated
below. If that's not what you want, then write back to the list with a fourth
column in you example that shows just what you want as the result.
Joseph Coveney
. version 11.1
.
. clear *
. set more off
.
. input long (QID Year PersonID)
QID Year PersonID
1. 1 2009 3
2. 1 2009 4
3. 2 2009 9
4. 2 2009 10
5. 2 2010 9
6. 2 2010 10
7. 2 2009 11
8. end
.
. *
. * Begin Here
. *
. bysort QID PersonID: generate long new_id = _n == 1
. quietly by QID: replace new_id = sum(new_id)
. list, noobs sepby(QID)
+--------------------------------+
| QID Year PersonID new_id |
|--------------------------------|
| 1 2009 3 1 |
| 1 2009 4 2 |
|--------------------------------|
| 2 2010 9 1 |
| 2 2009 9 1 |
| 2 2009 10 2 |
| 2 2010 10 2 |
| 2 2009 11 3 |
+--------------------------------+
. exit
end of do-file
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