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st: RE: RE: Making a local with no assigned value zero
From
"Nick Cox" <[email protected]>
To
<[email protected]>
Subject
st: RE: RE: Making a local with no assigned value zero
Date
Mon, 14 Jun 2010 21:14:52 +0100
4.
local x1 = `y1' + `x1'
(doesn't fit all problems, but might fit yours)
Nick
[email protected]
Nick Cox
There are various fixes. Here are some:
1.
if "`y1'" == "" local y1 = 0
local x1 = `x1' + `y1'
2.
local x1 = cond("`y1'" != "", `x1' + `y1', `x1')
3.
if "`y1'" != "" local x1 = `x1' + `y1'
Nick
[email protected]
George Chioran
My code goes like
this: local x1 = `x1’ + `y1’. I get the `y1’ variable through repeated loops
and sometimes `y1’ is not assigned any value.
When `y1’ does not
have any value, the line local x1 = `x1’ + `y1’ stops my program and I get an invalid
syntax error.
My question is: Could
I somehow make the local `y1’ to be equal to zero, or not to be taken into
consideration in my sum in case `y1’ is not assigned any value?
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