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Re: st: chi2 on aggregate results
From
mai7777 <[email protected]>
To
[email protected]
Subject
Re: st: chi2 on aggregate results
Date
Mon, 10 May 2010 13:24:56 -0400
Thanks for the quick response. I guess it was the "col" option that I
was looking for, but just to confirm: Below, is the Pearson chi2(1) =
5.9421 Pr = testing the hypothesis that the proportion of 76.67 in
a sample size of 30 equal to the proportion of 47.22 in a sample size
of 36?
. tabi 23 17 \ 7 19, chi col
| col
row | 1 2 | Total
-----------+----------------------+----------
1 | 23 17 | 40
| 76.67 47.22 | 60.61
-----------+----------------------+----------
2 | 7 19 | 26
| 23.33 52.78 | 39.39
-----------+----------------------+----------
Total | 30 36 | 66
| 100.00 100.00 | 100.00
Pearson chi2(1) = 5.9421 Pr = 0.015
On Mon, May 10, 2010 at 1:15 PM, Alan Neustadtl
<[email protected]> wrote:
> Are you looking for something like this?
>
> - tabi 23 17 \ 7 19, chi col -
>
>
>
> On Mon, May 10, 2010 at 1:08 PM, mai7777 <[email protected]> wrote:
>> hi,
>> I'm trying to conduct a chi2 on aggregate results to test that the
>> proportions of incidence across two treatments are the same:
>>
>> Treatment 1 has a total of 30 subjects, 23 of which had incidence
>> Treatment 2 has a total of 36 subjects, 17 of which had incidence.
>>
>> How do I do that?
>> Thanks!
>> *
>> * For searches and help try:
>> * http://www.stata.com/help.cgi?search
>> * http://www.stata.com/support/statalist/faq
>> * http://www.ats.ucla.edu/stat/stata/
>>
>
> *
> * For searches and help try:
> * http://www.stata.com/help.cgi?search
> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
>
*
* For searches and help try:
* http://www.stata.com/help.cgi?search
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/