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st: gllamm with numerical problems and the setup with discrete latent vars
From
Hey Sky <[email protected]>
To
statalist <[email protected]>
Subject
st: gllamm with numerical problems and the setup with discrete latent vars
Date
Thu, 6 May 2010 09:37:23 -0700 (PDT)
hey, all
just read the "ML numerical problems" and thought the problem I met
I am modeling training behavior with discrete latent variable. I assume there is
only one discrete latent variable, and the code is as following. it works well.
gen cons=1
eq mu1: cons
gllamm training_decision indep, i(id) base(5) link(mlogit) family(binom) ip(f) nrf(1) eq(mu1)
the result of upper code for latent variable:
Probabilities and locations of random effects
------------------------------------------------------------------------------
***level 2 (id)
loc1: -1.8365, .54899
var(1): 1.0082459
prob: 0.2301, 0.7699
my understanding to the loc1 is: the parameters for the discrete latent variable, type of person,
for all people. that is:
epsilon_i= alfa_0 + alfa_1*mu
mu is type of person which I assume two types here.
but how to model it if I assume people with different training decision have
different probility to belong to type 1 or 2 person?
I have tried the following code and hope I can get:
epsilon_i= alfa_edu_0 + alfa_edu_1*mu
epsilon_i= alfa_wrk_t0 + alfa_work_t1*mu
epsilon_i= alfa_wrknt0 + alfa_wrknt1*mu
the code:
eq mu1: training
eq mu2: work_with_training
eq mu3: work_no_training
gllamm training_decision indep, i(id) link(mlogit) family(binom) ip(f) nrf(3) eq(mu1 mu2 mu3)
but the computer reports numerical problems. I think some place in the code is wrong,
because of fortran have given result. any suggestions about it?
I wish I make myself clear and thanks a lot for any reply in advance
Nan
from Montreal
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