RE: st: to replace just one character of values of a variabl

["Martin Weiss" <martin.weiss1@gmx.de>]

<>

So, back on the home base, here is an example -replace-ing char(64) with nothing:

*******
clear*

inp str10 mystrvar
"hello"
"goo@d-bye"
"he@lo"
"goo@d-bye"
"hello"
"hello"
end

list, noo

replace mystrvar=subinstr(mystrvar,"`=char(64)'","",.)  

list, noo
*******


Your -replace- call did not say what you wanted Stata to do once the -if- qualifier was true.

HTH
Martin

-----Original Message-----
From: owner-statalist@hsphsun2.harvard.edu [mailto:owner-statalist@hsphsun2.harvard.edu] On Behalf Of Martin Weiss
Sent: Sonntag, 25. April 2010 21:54
To: statalist@hsphsun2.harvard.edu
Subject: RE: st: to replace just one character of values of a variabl

<>
Not so, as you have found out already. My mobile has no Stata, so I am  not able to comment authoritatively, but look at -help subinstr-.

HTH
Martin

-original message-
Subject: st: to replace just one character of values of a variabl
From: carmen gamarra <carmengamarra@hotmail.com>
Date: 25-04-2010 21:09

<>

Hello people,
 
I imagined that a variation of the same command 
*****
drop if strpos(mystrvar, "`=char(191)'")!=0
*********
 could be used to replace just one character of values of a variable.

I tried this but didn't function

*****
replace if strpos(var1, "`=char(64)'")!=0
*********

Please Help me!

 
Thanks Carmen 






<>
 
 
Stata will delete those happily if you find a way to tell it what to -drop-.
In this case, -ssc d asciiplot- by Nick Cox tells you which number to pass
to -char()- to check for the presence of the character:
 
*******
clear*
 
inp str10 mystrvar
"hello"
"goo¿d-bye"
"he¿lo"
"goo¿d-bye"
"hello"
"hello"
end
 
list, noo
 
drop if strpos(mystrvar, "`=char(191)'")!=0
 
list, noo
*******
 
 
HTH
Martin

<>

hello people,
 
 
Another question, stata could delete
all the row of a variable containing characters like
"¿", for example.
 
 
Thanks Carmen 
 		 	   		  
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