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st: RE: re: data row transformation for irregular consecutive days
From
"Nick Cox" <[email protected]>
To
<[email protected]>
Subject
st: RE: re: data row transformation for irregular consecutive days
Date
Mon, 22 Feb 2010 16:39:05 -0000
Thanks to Kit for the mention. For some Stata logic on working with
spells, see
SJ-7-2 dm0029 . . . . . . . . . . . . . . Speaking Stata: Identifying
spells
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . N.
J. Cox
Q2/07 SJ 7(2):249--265 (no
commands)
shows how to handle spells with complete control over
spell specification
Nick
[email protected]
Kit Baum
Kaspar said
Is there a fast way in Stata 11 to do this data transformation?
What I have:
symbol days
AAL 04-10-2004
AAL 10-01-2005
AAL 11-01-2005
AAL 12-01-2005
AAL 01-04-2005
AAL 04-04-2005
AAL 06-06-2005
AAL 07-06-2005
AAL 08-06-2005
What I need:
AAL 04-10-2004 04-10-2004
AAL 10-01-2005 12-01-2005
AAL 01-04-2005 01-04-2005
AAL 04-04-2005 04-04-2005
AAL 06-06-2005 08-06-2005
g date = date(var2,"DMY")
g en = _n
tsset en
// requires N J Cox -tsspell- from SSC (findit tsspell)
tsspell date, fcond(D.date>1)
bys _spell: g sdate = date if _seq==1
bys _spell: g ndate = date if _end
l
collapse sdate ndate, by(var1 _spell)
format sdate %td
format ndate %td
l
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