Sorry, I should have explained it better. nongroup_f = 1 when both
firm_id and nation_id are different for the given observation relative
to "at least one other observation" within the same contract_id. Thus
in the following case of contract_id=10, we have value 1 for all
observations for the nongroup_f variable. Martin's last response gives
the correct result. Thanks, joe.
10 4 CH 0 1 0 1
10 4 UK 0 1 0 1
10 5 US 1 0 0 1
10 5 US 1 0 0 1
10 6 NL 0 0 1 1
10 7 NL 0 0 1 1
On Tue, Nov 10, 2009 at 11:54 PM, Tim Wade <[email protected]> wrote:
> Maybe I am missing something obvious here, but I can't follow what you
> are trying to do either. This criterion:
>
>> 4 .nongroup_f = 1 when both firm_id and nation_id are different for
>> two or more observations with the same contract id
>
> does not seem to be consistent with this line listing:
>
>> 10 5 US 1 0 0 1
>> 10 5 US 1 0 0 1
>
> here are two observations with the same firm_id and nation_id yet
> nongroup_f is 1. However, you may want to try looking at some
> combinations of -duplicates, tag- and levelsof, this might help as an
> alternative approach.
>
> Tim
>
>
> On Tue, Nov 10, 2009 at 12:08 PM, joe j <[email protected]> wrote:
>> Thanks. The last 4 columns (group_d; group_f; nongroup_d; nongroup_f)
>> are the final output variables. Their definitions are below the table.
>>
>> ******
>> contract_id; firm_id; nation_id; group_d; group_f; nongroup_d; nongroup_f
>> 1 2 US 1 0 0 0
>> 1 2 US 1 0 0 0
>> 4 3 UK 0 1 0 0
>> 4 3 US 0 1 0 0
>> 8 3 US 0 0 1 1
>> 8 4 UK 0 1 0 1
>> 8 4 US 0 1 1 1
>> 9 3 US 0 0 1 1
>> 9 4 UK 0 0 0 1
>> 9 5 US 0 0 1 1
>> 10 4 CH 0 1 0 1
>> 10 4 UK 0 1 0 1
>> 10 5 US 1 0 0 1
>> 10 5 US 1 0 0 1
>> 10 6 NL 0 0 1 1
>> 10 7 NL 0 0 1 1
>> ******
>> 1. group_d = 1 when both firm_id and nation_id are same for two or
>> more observations with the same contract id
>> 2. group_f = 1 when firm_id is same but nation_id is different for
>> two or more observations with the same contract id
>> 3. nongroup_d = 1 when firm_id is different but nation_id is same for
>> two or more observations with the same contract id
>> 4 .nongroup_f = 1 when both firm_id and nation_id are different for
>> two or more observations with the same contract id
>>
>>
>> On Tue, Nov 10, 2009 at 5:47 PM, Martin Weiss <[email protected]> wrote:
>>>
>>> <>
>>>
>>>
>>> For clarification, you could provide the solution, i.e. the dummies that you
>>> actually want to see as your final output, for your chosen example. Makes it
>>> considerably easier to work towards code for you...
>>>
>>>
>>>
>>> HTH
>>> Martin
>>>
>>>
>>> -----Ursprüngliche Nachricht-----
>>> Von: [email protected]
>>> [mailto:[email protected]] Im Auftrag von joe j
>>> Gesendet: Dienstag, 10. November 2009 17:39
>>> An: [email protected]
>>> Betreff: Re: st: AW: forvalues & replace not working under two 'not equal
>>> to' conditions
>>>
>>> Thanks Martin. I think I wasn't clear enough in the last mail. I was
>>> not looking at various combinations of firm_id, nation_id and
>>> contract_id 'for each observation'. Rather I was looking at the
>>> similarity or difference of firm_id/nation_id 'between two or more
>>> observations' under each contract_id.
>>>
>>> Based on Martin's suggestion I could derive group_d (see below). But I
>>> still can't get right nongroup_f, which equals 1 (for all
>>> observations) if firm_id and nation_id are different for two or more
>>> observations under each contract_id (but it takes a value 1, wrongly,
>>> for all observations in the data)
>>>
>>> *deriving group_d (this works)
>>> egen groups=group(firm_id nation_id)
>>>
>>> bys contract_id (groups): /*
>>> */ gen byte distinctcount_group_d= /*
>>> */ (groups[_n]==groups[_n+1])
>>>
>>> bys contract_id (groups): /*
>>> */ replace distinctcount_group_d=1 /*
>>> */ if (groups[_n]==groups[_n-1])
>>>
>>> *2 deriving nongroup_f doesnt work (e.g. it should be 0 for contract_id=1)
>>> bys contract_id (groups): /*
>>> */ gen byte distinctcount_nongroup_f= /*
>>> */ (groups[_n]~=groups[_n+1]) & (nation_id[_n]~=nation_id[_n+1])
>>>
>>> bys contract_id (groups): /*
>>> */ replace distinctcount_nongroup_f=1 /*
>>> */ if (groups[_n]~=groups[_n-1]) & (nation_id[_n]~=nation_id[_n-1])
>>>
>>> On Tue, Nov 10, 2009 at 4:14 PM, Martin Weiss <[email protected]> wrote:
>>>>
>>>> <>
>>>>
>>>> I think a variable denoting the combinations between the three ids is a
>>> good
>>>> place to start for you:
>>>>
>>>>
>>>>
>>>> *************
>>>> clear*
>>>> inp byte(contract_id firm_id) nation_id:mylabel, auto
>>>> 1 2 "US"
>>>> 1 2 "US"
>>>> 4 3 "UK"
>>>> 4 3 "US"
>>>> 8 4 "US"
>>>> 8 4 "UK"
>>>> 8 3 "US"
>>>> 9 5 "US"
>>>> 9 4 "UK"
>>>> 9 3 "US"
>>>> 10 5 "US"
>>>> 10 5 "US"
>>>> 10 6 "NL"
>>>> 10 7 "NL"
>>>> 10 4 "UK"
>>>> 10 4 "CH"
>>>> end
>>>>
>>>> egen groups=group(contract_id firm_id nation_id)
>>>>
>>>> l, sepby(con) noobs
>>>> *************
>>>>
>>>>
>>>>
>>>> HTH
>>>> Martin
>>>>
>>>>
>>>> -----Ursprüngliche Nachricht-----
>>>> Von: [email protected]
>>>> [mailto:[email protected]] Im Auftrag von joe j
>>>> Gesendet: Dienstag, 10. November 2009 16:04
>>>> An: [email protected]
>>>> Betreff: st: forvalues & replace not working under two 'not equal to'
>>>> conditions
>>>>
>>>> My dataset has three variables 1. contract_id, 2. firm_id and 3.
>>>> nation_id. I want to create 4 variables, each of which gets a value of
>>>> 1 if certain conditions are met. The variables I want to create are
>>>> specific to the contract id, and are:
>>>>
>>>> 1. group_d = 1 when both firm_id and nation_id are same for two or
>>>> more firms with the same contract id
>>>> 2. group_f = 1 when firm_id is same but nation_id is different for
>>>> two or more firms with the same contract id
>>>> 3. nongroup_d = 1 when firm_id is different but nation_id is same for
>>>> two or more firms with the same contract id
>>>> 4 .nongroup_f = 1 when both firm_id and nation_id are different for
>>>> two or more firms with the same contract id
>>>>
>>>> The following code works well for the first three variables, but not
>>>> for the last, nongroup_f; the value is 1 for all observations. I can't
>>>> figure out why.
>>>>
>>>> This is a sample code:
>>>>
>>>> clear
>>>> inp str10(contract_id firm_id nation_id)
>>>> 1 2 "US"
>>>> 1 2 "US"
>>>> 4 3 "UK"
>>>> 4 3 "US"
>>>> 8 4 "US"
>>>> 8 4 "UK"
>>>> 8 3 "US"
>>>> 9 5 "US"
>>>> 9 4 "UK"
>>>> 9 3 "US"
>>>> 10 5 "US"
>>>> 10 5 "US"
>>>> 10 6 "NL"
>>>> 10 7 "NL"
>>>> 10 4 "UK"
>>>> 10 4 "CH"
>>>> end
>>>>
>>>>
>>>> *1.group_d . WORKS!
>>>> gen group_d=.
>>>> forvalues i=1/`=_N'{
>>>> bys contract_id: replace group_d=1 if firm_id==firm_id[_n-`i'] &
>>>> nation_id==nation_id[_n-`i']
>>>> }
>>>> forvalues i=1/`=_N'{
>>>> bys contract_id: replace group_d=1 if firm_id==firm_id[_n+`i'] &
>>>> nation_id==nation_id[_n+`i']
>>>> }
>>>>
>>>> *2.group_f WORKS!
>>>> gen group_f=.
>>>> forvalues i=1/`=_N'{
>>>> bys contract_id: replace group_f=1 if firm_id==firm_id[_n-`i'] &
>>>> nation_id!=nation_id[_n-`i']
>>>> }
>>>> forvalues i=1/`=_N'{
>>>> bys contract_id: replace group_f=1 if firm_id==firm_id[_n+`i'] &
>>>> nation_id!=nation_id[_n+`i']
>>>> }
>>>>
>>>> *3. nongroup_d WORKS!
>>>> gen nongroup_d=.
>>>> forvalues i=1/`=_N'{
>>>> bys contract_id: replace nongroup_d=1 if firm_id!=firm_id[_n-`i'] &
>>>> nation_id==nation_id[_n-`i']
>>>> }
>>>> forvalues i=1/`=_N'{
>>>> bys contract_id: replace nongroup_d=1 if firm_id!=firm_id[_n+`i'] &
>>>> nation_id==nation_id[_n+`i']
>>>> }
>>>>
>>>> *4.nongroup_f DOESN'T WORK!!
>>>> gen nongroup_f=.
>>>> forvalues i=1/`=_N'{
>>>> bys contract_id: replace nongroup_f=1 if (firm_id~=firm_id[_n-`i']) &
>>>> (nation_id~=nation_id[_n-`i'])
>>>> }
>>>> forvalues i=1/`=_N'{
>>>> bys contract_id: replace nongroup_f=1 if (firm_id~=firm_id[_n+`i']) &
>>>> (nation_id~=nation_id[_n+`i'])
>>>> }
>>>> *
>>>> * For searches and help try:
>>>> * http://www.stata.com/help.cgi?search
>>>> * http://www.stata.com/support/statalist/faq
>>>> * http://www.ats.ucla.edu/stat/stata/
>>>>
>>>>
>>>> *
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>>>> * http://www.ats.ucla.edu/stat/stata/
>>>>
>>>
>>> *
>>> * For searches and help try:
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>>> * http://www.stata.com/support/statalist/faq
>>> * http://www.ats.ucla.edu/stat/stata/
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>>> *
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>>>
>>
>> *
>> * For searches and help try:
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>
> *
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