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Am I right that for y=2 the z value does not matter at all? That is what I
take away from your description of the problem...
***
clear*
set obs 10000
gen x=rnormal()
centile x, ce(10)
local p10x=`r(c_1)'
gen z=rnormal()
centile z, ce(10)
local p10z=`r(c_1)'
gen y=cond(x<=`p10x' & z <= `p10z', /*
*/ 0, cond(x<=`p10x' & z > `p10z', 1, /*
*/ cond(x>`p10x',2,./*
*/ )/*
*/ )/*
*/ )
ta y
***
See NJC`s and coauthor`s
http://www.stata-journal.com/sjpdf.html?articlenum=pr0016
HTH
Martin
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Pancho Villa
Sent: Montag, 6. Juli 2009 22:01
To: [email protected]
Subject: Re: st: RE: Converting a continuous var into a binary var
Thank you, Nick and Martin. I abbreviated my problem for simplicity.
So much that I'm afraid the feedback I got from you is not helping me
much.
Actually, my variable y is not binary, but categorical with more than
2 possible values. My y depends on the 10th percentile values of x
and z, respectively. (In fact, it depends on the values of other
variables, but that's not problematic. This is the simplest
description of my problem that can get me helpful feedback from you.)
So, it's more like this:
y = 0 if x <= 10th percentile of x & z <= 10th percentile of z
y = 1 if x <= 10th percentile of x & z > 10th percentile of z
y = 2 if x > 10th percentile of x & z <= 10th percentile of z
y = 2 if x > 10th percentile of x & z > 10th percentile of z
I found that I can do this:
centile x z, centile(10)
which gives me the 10th percentiles of x and z in the same output.
But I don't know how to invoke the result for each variable in my next
lines. Truly basic.
Thanks again,
PV
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