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Re: st: Re: single sample pre/post comparison of proportions
From |
"Michael I. Lichter" <[email protected]> |
To |
[email protected] |
Subject |
Re: st: Re: single sample pre/post comparison of proportions |
Date |
Thu, 11 Jun 2009 13:10:55 -0400 |
Svend: The researcher who asked me about this likes the idea of
reporting CIs and forgoing the explicit hypothesis test.
José: Unfortunately, it looks like the server ate the first line of your
post so I'm not certain what you're suggesting. Is p(known) the
pre-intervention proportion of adopters, is it an external estimate, or
is it something else? If it's the first, I'm not sure I could justify
that as a benchmark.
Thanks to both of you for your suggestions.
Michael
José Maria Pacheco de Souza wrote:
bound p(known), test a hypothesis Ha: p(new)>p(known) vs H0:
p(new)=p(known), using the at risk of improving.
Or as Svend presented, just estimate the proportion of new, among
those at risk. In this case, aftward it will difficult to resist the
temptation to compare this result with the p(known).
Cheers,
José Maria
Jose Maria Pacheco de Souza, Professor Titular (aposentado)
Departamento de Epidemiologia/Faculdade de Saude Publica, USP
Av. Dr. Arnaldo, 715
01246-904 - S. Paulo/SP - Brasil
fones (11)3061-7747; (11)3768-8612;(11)3714-2403
www.fsp.usp.br/~jmpsouza
-----
Michael asked and Joseph responded (not shown) - and Michael then wrote:
The suggestion of a one-sample test restricted to pre-intervention
ADOPT=NO crowd makes sense. I think you are also sneakily suggesting
that the most obvious null hypothesis -- "H0: p = 0" is not a good
choice; there would probably be some adoption even in the absence of
the intervention, and the intervention probably cannot be called a
success unless the proportion of adopters exceeds a minimum
cost/benefit threshold. Instead, I could choose, e.g., "H0: p < .25"
(a one-tailed test). That seems reasonable.
===============================================================
I wonder whether a P-value related to a somewhat arbitrary null
hypothesis is useful. I think the following is more informative:
Assume that you had 90 participants, 40 of whom already had the good
habit, leaving 50 "at risk" for improvement. 20 (40%) of these
improved. The 95% CI for this estimate is 26%-55%:
. cii 50 20 , binomial
-- Binomial
Exact --
Variable | Obs Mean Std. Err. [95% Conf.
Interval]
-------------+---------------------------------------------------------------
| 50 .4 .069282 .2640784 .548206
Hope this helps
Svend
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--
Michael I. Lichter, Ph.D. <[email protected]>
Research Assistant Professor & NRSA Fellow
UB Department of Family Medicine / Primary Care Research Institute
UB Clinical Center, 462 Grider Street, Buffalo, NY 14215
Office: CC 125 / Phone: 716-898-4751 / FAX: 716-898-3536
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