<>
When you -trace- the execution, you see that -tin()- expects the format in
which the data were -tsset- while you are passing it an unformatted date.
You can achieve what you want with the code below, though... See -help
extended_fcn-
*************
// begin example code
// Define today
local today = date(c(current_date),"DMY")
disp `today'
disp %td `today'
local today2: disp %td `today'
// Create synthetic dataset
use sp500, clear
gen datenew = date + int(365.25*8)
format datenew %td
drop date
tsset datenew
order datenew
drop if tin(01jul2009,)
// Display data
list in -15/l // OK
list if datenew >= `today' // OK
list if tin(09jun2009,) // OK
list if tin(`today2',) // OK
list if tin(`today',) // Error
// end example code
*************
HTH
Martin
-----Ursprüngliche Nachricht-----
Von: [email protected]
[mailto:[email protected]] Im Auftrag von Michael Hanson
Gesendet: Dienstag, 9. Juni 2009 06:51
An: [email protected]
Betreff: st: Using date locals with -tin()-
I would like to get the -tin()- function to recognize the current
date, such as in the example proposed below. If you run this example
today (as in 2009-Jun-09), the first three list commands should yield
the same results, while the last does not work due to a syntax error.
I'm guessing that is because `today' evaluates to 18057 instead of
09jun2009 in the -tin()- function (for today, that is), but I'm not
sure. Suggestions on how to use (some form of) the local macro
`today' inside the -tin()- function would be appreciated.
// begin example code
// Define today
local today = date(c(current_date),"DMY")
disp `today'
disp %td `today'
// Create synthetic dataset
webuse sp500, clear
gen datenew = date + int(365.25*8)
format datenew %td
drop date
tsset datenew
order datenew
drop if tin(01jul2009,)
// Display data
list in -15/l // OK
list if datenew >= `today' // OK
list if tin(09jun2009,) // OK
list if tin(`today',) // Error
// end example code
Thanks in advance for any assistance.
-- Mike
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