Carlo specified Stata 9.2; so he would need to use
125 + 25 * invnormal(uniform())
Not rnormal(125,25).
Otherwise Eva's reply shows that Carlo's question is open to various
interpretations
Nick
[email protected]
Eva Poen
If you put such a constraint on your random values, it means that at
most 76 of them can be random; you need one value to bring the sum up
to 9900. This is very simple to do:
clear
set obs 77
set seed 123
gen n = rnormal(125,25) in 1/76
qui sum n
replace n = 9900-r(sum) in 77
You didn't mention what kind of random values you want, i.e. which
distribution. I assumed normal distribution with mean 125 and sd of
25.
2009/3/25 Carlo Lazzaro <[email protected]>:
> is there any way for imposing Stata 9.2/SE to create a variable
composed of
> 77 random values so that the sum of these random values is 9900?
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