OK. I used the correct expression and -set trace on-. Here's the feed back:
--------------------------------------------------------------------
end nlsurwbe ---
- }
- if _rc {
- di as error "nlsur`eqn' returned " _rc
= di as error "nlsurwbe returned " _rc
nlsurwbe returned 111
- di as error "verify that nlsur`eqn' is a function evaluator program"
= di as error "verify that nlsurwbe is a function evaluator program"
verify that nlsurwbe is a function evaluator program
- exit _rc
}
}
---------------------------------------------------------------- end
nlsur.Estimate ---
end nlsur ---
r(111);
What does that mean?
Jingjing
Quoting Nick Cox <[email protected]>:
(1) is incorrect, because it is illegal syntax. Stata won't know
what to do with the unmatched quotes.
(2) is legal syntax. I can't say whether it is correct for your
problem, but provided all the locals are defined, it looks OK to me.
But it is better to get Stata to tell you this.
Nick
[email protected]
[email protected]
Sorry, I am a little confused. Two expressions:
(1) replace `lnc'=`a'*`lnpe'+`b'*``lnpe'*`lnpe''
(2) replace `lnc'=`a'*`lnpe'+`b'*`lnpe'*`lnpe'
Which is the correct one?
Quoting Nick Cox <[email protected]>:
``lnpe' or `lne'' can not be legal. As in ordinary language, single
quotes must be in matching pairs.
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