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st: -xtnbreg- vs. -nbreg, cluster()-
Hello all,
I'm trying to figure out how, precisely, -xtnbreg- differs from
-nbreg- (with or without the clustering option).
I have monthly safety data from a company over several years. The
company has many different facilities, and I am trying to look at how
characteristics of the facilities affect safety. In particular, there
was a policy change at a certain time (a change which only affected a
subset of facilities), and I want to see if that policy resulted in
fewer accidents.
The data is panel data organized thusly:
month | facility | accidents | policy | hours_worked |
------------------------------------------------------------------------------------------------
2000m1 | 001 | 0 | old | 1500 |
...
2005m12 | 001 | 3 | old | 1625 |
...
2000m1 | 001 | 0 | old | 1800 |
...
2005m12 | 999 | 2 | new | 1100 |
etc.
Because accidents are count data, and there is evidence of
overdispersion, I am using a negative binomial regression:
- nbreg accidents policy hours_worked, cluster(facility) -
(I don't believe that hours_worked is a strict exposure variable,
since higher-production months may have different characteristics than
lower-production months (e.g. new, greener, workers), which is why I
don't use it as exposure explicitly, but include it as an independent
variable.)
My question is, what is the difference between doing it as I do above,
vs. setting the data as panel (-xtset facility month-) and using
-xtnbreg- (either fe or re) which has no clustering option?
The facilities are (or, I believe they are) homogeneous, so I'm not
looking to extract the fixed effects between facilities, but the
estimates I get from -xtnbreg- are all lower than from -nbreg-. Is
this evidence that my assumption of homogeneity is incorrect? Or am I
otherwise mispecifying my model?
Thank you for any suggestions/assistance you have.
--
Brian Karfunkel
Research Fellow
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