Dear Martin,
I don't know if I got what you mean, but as far as I know your proposal using -summarize, meanonly- would lead to the average (across the most recent three years) of the mean (across observations within each year).
But I want to get the average (across the most recent three years) of the median (across observations within each year), i.e. average1997=(median1997+median1996+median1995)/3
Hope someone could help me.
Fabian
[I guess your proposal would look like the following:
quietly forvalues k = 1/10 {
quietly forvalues y = 1974/2000 {
summarize age if year == `= `y' - 3' & group == `k', meanonly
local median3 = r(mean)
summarize roe if year == `= `y' - 2' & group == `k', meanonly
local median2 = r(mean)
summarize roe if year == `= `y' - 1' & industry == `k', meanonly
replace fiveyearmedian = (`median3' + `median2' + r(mean1 ) / 3 if year == `y' & group == `k'
}
}
-------- Original-Nachricht --------
> Datum: Fri, 3 Oct 2008 14:22:16 +0200
> Von: "Martin Weiss" <[email protected]>
> An: [email protected]
> Betreff: st: Re: creating average over past three years within groups
> Not sure what you are doing with all those -locals-. Just -summarize,
> meanonly- with your -if- statements and type -ret li- afterwards. There
> you
> will find the average as r(mean) to plug into your -replace- operation.
>
> HTH
> Martin
> _______________________
> ----- Original Message -----
> From: "Fabian Brenner" <[email protected]>
> To: <[email protected]>
> Sent: Friday, October 03, 2008 2:17 PM
> Subject: st: creating average over past three years within groups
>
>
> > Dear all:
> >
> > I used -bysort year group : egen oneyearmedian = median(age)- to create
> > the median within each group (1-10) for each year (1974-2000).
> >
> > Now I want to get the three year average of the three median for each
> > group for the most recent three years:
> >
> > generate threeyearaverage = .
> > sort year group
> >
> > quietly forvalues k = 1/10 {
> > quietly forvalues y = 1974/2000 {
> > local median3 = oneyearmedian if year == `= `y' - 3' & industry == `k',
> > local median2 = oneyearmedian if year == `= `y' - 2' & industry == `k',
> > local median1 = oneyearmedian if year == `= `y' - 1' & industry == `k',
> > replace fiveyearmedian = (`median3' + `median2' + `median1' ) / 3 if
> year
> > == `y' & group == `k'
> > }
> > }
> >
> > But stata always says: if not allowed r(101);
> >
> > What do I wrong? Hope someone can help me.
> > Fabian Brenner
> >
> >
> > --
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> >
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Jetzt dabei sein: http://www.shortview.de/wasistshortview.php?mc=sv_ext_mf@gmx
*
* For searches and help try:
* http://www.stata.com/help.cgi?search
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
