Re: st: Time of day

["Marc N. Sch�ssler" <marc.schuessler@medma.uni-heidelberg.de>]

Hi Alexander,
i suggest you to get a numeric date based on milliseconds and then  
grap with the time of day- funktion the needed component, here hours  
(type "help date" and there see "extracting date and time components").

gen double timevar = clock(result_date,  "DMYhms")
gen hourvar = hh(timevar)

you might want to keep your new timevar, then bring it with
format timevar %tc
to a more readable format.

hope this helpes you
Marc




Am 28.08.2008 um 12:54 schrieb <Alexander.Severinsen@telenor.com>  
<Alexander.Severinsen@telenor.com>:


> Dear Statalister,
>
> I use Stata 10. I have a string variable, result_date, that records  
> day, month, year, hours, minutes, seconds. It displays, 11.02.2008  
> 08:21:00.000
>
> I would like to generate a new variable that only indicates hours.  
> I had a look at the ntimeofday, written by Nicholas J. Cox (findit  
> ntimeofday), and issed the following command,
>
> ntimeofday result_date, gen(ndatetime) s(dmy h mi s) n(h)
>
> It runs ok, but listing some of these values gives me
>
> list ndatetime in 1/2
>   | ndatetime |
>      |-----------|
>   1. | 421760.35 |
>   2. | 421759.92 |
>
> I am not sure whether I am on the right track, and maybe all I am  
> missing is to translate these numbers into hours? Any help would be  
> greatly appreciated.
>
> Best wishes,
> Alexander Severinsen
>
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