I am not clear what your question is precisely.
But if you want to -regress- on something and its square, you need to
-generate- the square as a new variable before you can do it, unless it
exists already.
I am not clear what you mean by "efficient", but I don't think there is
another way to do it.
Nick
[email protected]
Meric Osman
I have a problem about writing my regression equation. I want to add
the variable and its square at the same time. Such as
y = a + a^2 + ...
Actually, I can do it by generating a new variable which is a*a, but I
don't wanna do that because it is not an efficient way.
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