Hi nick,
Thanks very much for that, what you suggest is exactly what I needed. I
think it must been my wording of what I wanted to achieve that prompted
the complicated approach.
This was the original statement of the problem... In an earlier post
1. Start with the first date.
2. See if the next date is more than 730 days from it. if its less than
73o days away from the first date drop it.
3. If it is more than 730 days away keep it and
4. Now this date becomes the reference date and the difference between
this date and the next is calculated and so on
However, Scotts approach to use mod and your final suggestion was all that
was needed.
Thank you
Regards
Rajesh
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of n j cox
Sent: 19 May 2008 15:37
To: [email protected]
Subject: Re: st: keeping dates which are n periods apart
The word description of your problem -- concisely given in your title --
suggests a simple solution based on Scott Merryman's excellent
suggestion of -mod(,)- as a basis for your problem.
keep if mod(year, 3) == mod(1987, 3)
gives the solution that you specify for the first example. The choice of
1987 reflects the fact that 1987 is the start of your first example.
Note that this
1. Does not entail any attention to the panel structure of your data.
2. Ensures that the same years are selected for all panels when available.
3. Can be transferred to other periods by changing 3 to what is desired.
4. Can be modified easily for aspects of the problem not specified. For
example, you could calculate mod(year, 3) and choose a start based on
what kept most observations. Or, very irregular panels might be sampled by
bysort id (year) : keep if mod(year, 3) == mod(year[1], 3)
which for the second example below (different from the first) selects
1986(3)1995.
Conversely, I don't understand why much more complicated solutions have
been offered for this kind of problem. What am I missing?
Nick
[email protected]
Rajesh Tharyan
I have this ( a subset of the original dataset, the original dataset has
about 6000 ids with an average of 6 years each)
id year
4 1987
4 1988
4 1989
4 1990
4 1992
4 1993
4 1994
9 1987
9 1988
9 1989
9 1990
9 1992
9 1993
9 1994
I need to keep years if they are more than 2 years apart by company. In an
earlier post
http://www.stata.com/statalist/archive/2006-02/msg00952.html
David Harrison suggested the following which works fine with one id
local refdate = year[1]
gen byte dropflag = 0
forvalues i = 2/`=_N' {
if year[`i']-`refdate'<=2 {
replace dropflag = 1 in `i'
}
else {
local refdate = year[`i']
}
}
drop if dropflag
drop dropflag
However I am not able to do it by id. what I would want is this..
id year
4 1987
4 1990
4 1993
9 1987
9 1990
9 1993
I tried using the above code with levelsof and foreach as shown below but no
luck.
*******************
input id year
4 1987
4 1988
4 1989
4 1990
4 1992
4 1993
4 1994
9 1986
9 1987
9 1988
9 1989
9 1990
9 1992
9 1993
9 1994
9 1995
9 1996
9 1997
end
levelsof id, local(levels)
foreach l of local levels {
qui sum year
local refdate = year[1]
gen byte dropflag = 0
forvalues i = 2/`=_N' {
if year[`i']-`refdate'<=2 {
replace dropflag = 1 in `i'
}
else {
local refdate = year[`i']
}
}
drop if dropflag
drop dropflag
}
list, table clean noobs
*******************
which gives me
id year
4 1987
4 1990
4 1993
9 1996
I tried a variation of the above as
**Snip**
levelsof id, local(levels)
foreach l of local levels {
qui sum year if id==`l'
local refdate = r(min)
local m= r(N)
gen byte dropflag = 0
forvalues i = 2/`m'{
if year[`i']-`refdate'<=2 {
replace dropflag = 1 in `i'
}
else {
local refdate = year[`i']
}
}
drop if dropflag & id==`l'
drop dropflag
}
**Snip**
That gives me
id year
4 1987
4 1990
4 1993
9 1995
9 1996
9 1997
Any pointers much appreciated
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