gen datef = date(datestr, "dm19y")
Note d m and y are lower case. Upper case does NOT work.
>>> On 4/7/2008 at 12:38 PM, in message <36739297C5CC416EA68C8F91171E6D2F@M2300>,
"Nuno" <[email protected]> wrote:
> Hi everyone,
>
> I'm haing a problem with the date function when trying to convert a string
> variable into a date variables. My string variable is datestr and contains
> dates in the following format "31/12/94", ie, DMY. I've tried to use the
> date function using the following syntax:
>
> gen datef = date(datestr, "DMY")
>
> I've already used this deffinition and it worked well, but the date had the
> format "31/12/1994". Is there a way of using the date function with the
> format I'm currently using, ie, with the last two digits in year?
>
> Best,
>
> Nuno
>
> *
> * For searches and help try:
> * http://www.stata.com/support/faqs/res/findit.html
> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
*
* For searches and help try:
* http://www.stata.com/support/faqs/res/findit.html
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
