Honorati Masanja and Maarten:
It's usually better to work with integers and divide on the fly:
forval i=2/8 {
lowess lnu5m year, bwidth(`=`i'/10') gen(alph`i')
}
or equivalently
forval i=2/8 {
local j=`i'/10
lowess lnu5m year, bwidth(`j') gen(alph`i')
}
though your example indicates you want 61 iterations, not 7, like so:
forval i=20/80 {
lowess lnu5m year, bwidth(`=`i'/100') gen(alph`i')
}
I also recommend -lpoly- (for Stata 10, -findit locpoly- for older
Stata) over -lowess- for speed reasons, at least. Try this:
forval i=1/18 {
lpoly lnu5m year, bw(`=`i'/10') gen(alph`i') at(year) deg(1) nogr
}
sc lnu5m year || line alph1-alph18 year, sort
in Stata 10, or
forval i=1/18 {
locpoly lnu5m year, w(`=`i'/10') gen(alph`i') at(year) deg(1) nogr
}
sc lnu5m year || line alph1-alph18 year, sort
in older Stata.
On Dec 1, 2007 6:09 AM, Maarten buis <[email protected]> wrote:
> --- Honorati Masanja <[email protected]> wrote:
> > I'm running a lowess regress and have the follow code which I'll
> > appreciate your help
> >
> > forval i=0.2(0.1)0.8 {
> > lowess lnu5m year, bwidth(`i') gen(alph`i')
> > }
> >
> > What I want is to have the variables alph as follows,
> >
> > if i=0.2 then alph20
> > if i=0.21 then alph21
>
> forval i=0.2(0.1)0.8 {
> local j = `i' * 100
> lowess lnu5m year, bwidth(`i') gen(alph`j')
> }
>
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