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st: Re: RE: RE: Identifier from three variables
my mistake. do not consider the previous email
----- Original Message -----
From: "Rafael Osorio" <[email protected]>
To: <[email protected]>
Sent: Monday, July 30, 2007 1:45 PM
Subject: st: RE: RE: Identifier from three variables
Other way of doing it, supposing each identifier is <= 99:
gen id = house*1000+family*100+individual
By doing it this way you can tell to which house and family a specific
person belongs to. If your data was not sorted by the identifiers, if you
sort by this new identifier the result will be equal to sorting it by all
identifiers. If your final id is large: gen double id...
If your identifiers are greater than 99, adjust the multipliers.
Rgds,
Rafael
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Nick Cox
Sent: Friday, July 27, 2007 2:09 PM
To: [email protected]
Subject: st: RE: Identifier from three variables
I'll answer this myself:
1. Don't do that. Use -egen, group()- with the -label- option.
2. See also
FAQ . . . . . . . . . . . . . . . . . . . . . . Creating group
identifiers
3/01 How do I create individual identifiers numbered
from 1 upwards?
http://www.stata.com/support/faqs/data/group.html
3. If you really must, look into -egen, concat()-, including
its options.
Nick
[email protected]
N�dia N. Sim�es
How can I generate an identifier from three variables?
In my data I have a column for the house, one for the family
and one for the individual
example:
house family individual
1 1 1
1 1 2
1 1 3
2 1 1
2 1 2
...
and I would like to know how can I create an identifier per
individual such as:
individual
010101
010102
010103
020101
...
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