Thanks this one has a better distribution of years equally among years.
Nancy
>>> "Austin Nichols" <[email protected]> 3/8/2007 1:38 pm >>>
On second thought, probably not.
My example code generates rndyear on the endpoints about half as often
as interior years. If you want rndyear to be randomly distributed as
an integer on the interval [Min,Max] then you can:
gen rndyear=Miny+round(uniform()*(Maxy-Miny+1)-.5)
as shown in this example:
clear
range id 1 200000 200000
gen Minyear=1990+floor(10*uniform())
gen Maxyear=Minyear+floor(10*uniform())
gen rndyear=Miny+round(uniform()*(Maxy-Miny+1)-.5)
gen dy=Max-Min+1
gen ril=(rndy-Miny)/(Maxy-Miny)
su ril
tab ril if dy==10
di "Percent should be close to 10%"
gen ryear=Miny+round(uniform()*(Maxy-Miny))
gen r2=(ry-Miny)/(Maxy-Miny)
tab r2 if dy==10
di "Endpoints p=" %3.2f 100/18 ", interior p=" %3.2f 100/9
On 3/8/07, Austin Nichols <[email protected]> wrote:
> Like so?
>
> clear
> range id 1 2000 2000
> gen Minyear=1990+floor(10*uniform())
> gen Maxyear=Minyear+floor(10*uniform())
> gen rndyear=Miny+round(uniform()*(Maxy-Miny))
> su
>
> or perhaps you mean
> gen rndyr=cond(uniform()>.5,Miny,Maxy)
> ?
>
> On 3/8/07, Nasreen Khan <[email protected]> wrote:
> > I want to assign a random number based on the values of two variables.
> > My data set looks like this.
> >
> > ID Minyear Maxyear
> > Nancy 1993 1994
> > Ramon 1996 1999
> > Eva 1992 1992
> >
> > I want to create a variable called randomyear such that the year is randomly assignment between minyear and maxyear value.
>
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