Sorry for a typo. Otherwise the solution to this different
problem is tacit in my reply.
by pid : gen work7 = emplo == 7 & work[8] != 1
Nick
[email protected]
[email protected]
> The length of study is 8 years. If the
> period of work was 7 years without a
> break, then there are only two possibilities:
> the person did not work in the first year
> or the person did not work in the last year.
YES I WANT ONLY 1 POSSIBILITY NOT WORK LAST YEAR
> by pid : egen emplo = count(work == 1)
> by pid : gen work7 = count == 7 & (work[1] != 1 | work[8] != 1)
I PUT EMPLO TO PLACE COUNT==7 (I don't have results if I put count==7)
but don't work. Because when I tab work7 I have obs in the wave 8
(work7==1), and is not correct in the wave 8 I want only work7==0.
my squence is 11111110
thank you very much
> Nick
> [email protected]
>
> [email protected]
>
>> I have a question about how calculate the number of years
>> work continuously.
>> I have a panel of 8 year and I want calculated the person how
>> has work
>> for 7 years no stop. (1111110)
>> I used this procedure:
>> by pid : egen emplo=count(work==1)
>> here work is=1 if work. after I did the tab emplo and I have
>> the table
>> for 8 years.
>> but there aredifferente sequence how 0111111, or 1011111 ecc and I
>> want only 1111110.
>>
>> for ex: 1011111 but is incorrect
>> pid emplo wave work
>> 1 7 1 1
>> 1 7 3 1
>> 1 7 4 1
>
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