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From | "Nikolaos A. Patsopoulos" <npatsop@cc.uoi.gr> |
To | statalist@hsphsun2.harvard.edu |
Subject | Re: st: weighted regression --- *PLEASE IGNORE THE POST* |
Date | Thu, 18 Jan 2007 12:33:51 +0200 |
Nikolaos A. Patsopoulos wrote:
Dear statalist members,Sorry for this, wrong weight used ( aweight instead of the correct fweight). STATA as it seems does correct automatically weighted SEs (not like SPSS).
in a weighted regression with what do I have to divide the weighted SE to get the unweighted one?
Some sample data and results:
WEIGHTED
var1 var2 weight
0 3.4 1
1 4.7 2
2 9.2 2
regress var2 var1 [aweight= weight]
(sum of wgt is 5.0000e+00)
Source | SS df MS Number of obs = 3
-------------+------------------------------ F( 1, 1) = 9.37
Model | 16.4437701 1 16.4437701 Prob > F = 0.2010
Residual | 1.75542889 1 1.75542889 R-squared = 0.9035
-------------+------------------------------ Adj R-squared = 0.8071
Total | 18.199199 2 9.09959951 Root MSE = 1.3249
------------------------------------------------------------------------------
var2 | Coef. Std. Err. t P>|t| [95% Conf. Interval]
-------------+----------------------------------------------------------------
var1 | 3.128571 1.022203 3.06 0.201 -9.859744 16.11689
_cons | 2.485714 1.445613 1.72 0.335 -15.88254 20.85397
------------------------------------------------------------------------------
UNWEIGHTED
var1 var2
0 3.4
1 4.7
2 9.2
1 4.7
2 9.2
. regress var2 var1
Source | SS df MS Number of obs = 5
-------------+------------------------------ F( 1, 3) = 28.10
Model | 27.4062836 1 27.4062836 Prob > F = 0.0131
Residual | 2.92571481 3 .97523827 R-squared = 0.9035
-------------+------------------------------ Adj R-squared = 0.8714
Total | 30.3319984 4 7.58299959 Root MSE = .98754
------------------------------------------------------------------------------
var2 | Coef. Std. Err. t P>|t| [95% Conf. Interval]
-------------+----------------------------------------------------------------
var1 | 3.128571 .5901689 5.30 0.013 1.25039 5.006752
_cons | 2.485714 .8346249 2.98 0.059 -.1704347 5.141863
------------------------------------------------------------------------------
I believe I have to divide the weight SE (1.022203) with the ResidualMS (1.75542889), which gives 0.582309.
Is this correct?
Thanks in advance,
Nikos
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