The macro doesn't work right in my example, below, b/c the local macro, time, is not defined yet. I use the global macro, timeconstraint, in a program with an argument called "time", so I thought that `time' would be defined w/in that program. However, this doesn't seem to be passing into the macro as I intended. The solution is to alter the program get_timeconstraint to take a second argument, time, and call this before trying to use the global macro, timeconstraint.
On Wed, 18 Oct 2006 8:17:39 -0400, dferry <[email protected]> wrote:
> Dear Statalisters,
> I apologize for the mundane post, but compound quotes always give me
> trouble. I think this is a time to use them, but I can't quite figure out
> how to specify them. I want to write a little program that will specify a
> global macro ($timeconstraint) that contains a reference to a local macro
> (`time') that will be defined in the program in which the global macro
> will be used. As I've written it, below, the local macro (`time') doesn't
> appear if I display the global macro ($timeconstraint). I've tried various
> combinations of compound quotes, but can't seem to get it right. Can
> someone offer help, please?
>
> capture program drop get_timeconstraint
> program get_timeconstraint
>
> version 9
> args runNum
>
> if "`runNum'"=="1" {
> global timeconstraint "time>=`time'-12 & time<=`time'"
> }
>
> else {;
> global timeconstraint "time==`time'"
> }
>
> end
>
> . get_timeconstraint 1
>
> . di "$timeconstraint"
> time>=-12 & time<=
>
> Thank you.
>
> Sincerely,
> Danielle Ferry
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