Michael and Svend are clearly spot on
in suggesting that the key to this
is getting the day before the first
day of the next month.
In addition, -egenmore- on SSC has carried
canned -egen- functions to do this for about
six years now.
Nick
[email protected]
Svend Juul
How about this:
// Create 3 dates for the exercise:
clear
input d m y
20 1 1991
10 3 2005
24 12 2005
end
gen date=mdy(m,d,y)
drop m d y
format date %d
// Here we go:
gen dd = day(date)
gen mm = month(date)
gen yyyy = year(date)
gen mm1=mm+1 if mm<12
replace mm1=1 if mm==12
replace yyyy=yyyy+1 if mm==12
gen date1 = mdy(mm1,1,yyyy)-1
format date1 %d
list
I just subtracted 1 from the first day in the following month.
But note the small "complication" with December.
Michael Blasnik
> No, but it's a fairly simple calculation, just subtract 1 day
> from the first
> of the next month and make sure to deal with December dates:
>
> gen newdate=mdy( month(date)+1,1,year(date))-1
> replace newdate=mdy(12,31,year(date)) if month(date)==12
>
> It could be done in a single line by combining these using cond()
Nuno Soares
> > I'm converting a set of dates to the end of the respective
> month, for
> > instance:
> > 20Jan91 -> 31Jan91
> > 10Mar05 -> 30Mar05
> > Etc.
> >
> > Does anyone knows a function in Stata that does this automatically?
*
* For searches and help try:
* http://www.stata.com/support/faqs/res/findit.html
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
