You refer cpi[] as a matrix but you told us it is a variable.
I am not complete clear about your data... but you can
try something like
forvalues i=1951/2003 {
local k=`i'-1950
local factor = cpi in `k'
gen realearnings`i'=earnings`i'/`factor'
}
Rodrigo.
program define real
1. local i=1951
2. while (`i'<=2003) {
3. replace j=`i'-1950
4. gen realearnings`i'=earnings`i'/cpi[`j',1]
5. local i=`i'+1
6. }
7. end
----- Original Message -----
From: "Seyda G Wentworth" <[email protected]>
To: <[email protected]>
Sent: Monday, October 02, 2006 3:42 PM
Subject: st: using matrix expression
Hi,
I have thousands of observations (individuals) and earnings data for each of
them covering 53 years, in the form earnings1951,
earnings1952,...,earnings2003.
I'd like to convert those nominal earnings to 2003 dollars.
I have a price index variable called cpi with 53 values * for each of the 53
years, where the first value is equal to cpi1951/cpi2003, the second is
cpi1952/cpi2003 etc. The remaing values are missing (because I copied a
column created in excel).
I'm trying to write a mini program that'll compute real earnings (in 2003
dollars) for all individuals the following way:
gen j=0
program define real
1. local i=1951
2. while (`i'<=2003) {
3. replace j=`i'-1950
4. gen realearnings`i'=earnings`i'/cpi[`j',1]
5. local i=`i'+1
6. }
7. end
But the results I get are incorrect. To check why, I try:
gen realearnings1951=earnings1951/cpi[1,1]
and get an error message saying:
cpi not found
r(111);
What is the correct way of doing this computation?
Thanks.
*
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*
* For searches and help try:
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* http://www.ats.ucla.edu/stat/stata/