Nick
[email protected]
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]]On Behalf Of Nick Cox
> Sent: 06 September 2006 17:33
> To: [email protected]
> Subject: RE: st: reorganizing data
>
>
> It can be done.
>
> Here is one solution. It is easiest if you know
> in advance roughly the maximum number of "others"
> any person might have.
>
> Warning: untested code ahead.
>
> Guess this number, and then add some. Suppose
> you guess 20, and then add 10. You get 30
>
> forval i = 1/30 {
> gen Other`i' = ""
> }
>
> levelsof Person, local(Persons)
> qui foreach P of local Persons {
> levelsof City if Person == "`P'", local(Cities)
> local which
> foreach C of local Cities {
> levels Person if Person != "`P'" & City == "`C'", ///
> local(work) clean
> local which : list which | work
> }
> noi di "`P': `which'"
> local nothers : word count `which'
> tokenize `which'
> forval i = 1/`nothers' {
> replace Other`i' = "``i''" if Person == "`P'"
> }
> }
>
> Then clean up any empty variables:
>
> forval j = 30(-1)1 {
> assert Other`i' == ""
> drop Other`i'
> }
>
> This loop is designed to fail at the first
> Other? variable that is not all empty. It
> will drop in turn Other30, Other29, ... if
> and only if it is all empty.
>
> Alternatively, -dropmiss- from STB-60 can be used.
>
> 30 is just pulled out of the air. Your number will differ.
>
> Nick
> [email protected]
>
> Anna Lehman
>
> > Going back to your suggestion,
> > If the number of observations is large and the information
> > does not fit into
> > a string variable,
> > is there any way I can still store the obtained information?
> > For example, since for person 1, the list is: 2, 5 4 and 8,
> > Others would contain a string with "2 5 4 8". That is fine.
> > The problem is
> > that if the list has many numbers they won't fit into the
> > variable "Others".
> > Can I store the different numbers (2,5, 4 and 8) in different
> > columns/variables (instead of creating the variable Others)?
> > This is the
> > only way I can think of dealing with a large number of
> > observations but I'm
> > not sure how to operationalize it... Any suggestions?
> > Thanks for your help,
> > Anna
> >
> > >From: n j cox <[email protected]>
> > >Reply-To: [email protected]
> > >To: [email protected]
> > >Subject: Re:st: reorganizing data
> > >Date: Mon, 04 Sep 2006 15:25:01 +0100
> > >
> > >This should work with toy datasets. If your identifiers are
> > >long, or your number of observations is large, the information
> > >won't fit into a string variable, so the lines mentioning
> > >"Others" should be deleted.
> > >
> > >gen Others = ""
> > >levelsof Person, local(Persons)
> > >qui foreach P of local Persons {
> > > levelsof City if Person == "`P'", local(Cities)
> > > local which
> > > foreach C of local Cities {
> > > levels Person if Person != "`P'" & City ==
> > "`C'", /// local(work)
> > >clean
> > > local which : list which | work
> > > }
> > > noi di "`P': `which'"
> > > replace Others = "`which'" if Person == "`P'"
> > >}
> > >
> > >Nick
> > >[email protected]
> > >
> > >Anna Lehman
> > >
> > >I have a dataset with the following structure:
> > >
> > >City Person_id
> > >A 1
> > >A 2
> > >B 1
> > >B 5
> > >C 1
> > >C 5
> > >C 4
> > >D 8
> > >D 1
> > >
> > >I would like to obtain the following:
> > >for each and every person, a list with the people that have
> > apartments in
> > >the same city (independently of which city). For example,
> > for person 1,
> > >this
> > >list would be: 2, 5 4 and 8. And for person 5 the list
> would be: 1 .
> > >
> > >Can you think of a relatively easy way of acomplishing this?
>
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