Sorry I did not state my question well. there are different racial groups in my
sample. What i want to do is to give each racial group a sequential number.
for example, I have 17 whites, 5 blacks and 7 others. then the value of the
sequential variable I created would be: 1 2 3....17 for whites; 1 2 ...5 for
blacks;
1 2 ....7 for others. what I was originally thinking is:
gen sequence=1
replace sequcence=sequence+1 if l.race==race
However, this does not work out as I thought.
Min
Quoting Nick Cox <[email protected]>:
> I am not aware of a lag function, i.e. -lag()-, in Stata. There is
> a lag operator L. but that is not appropriate for your purpose.
>
> You may be in search of
>
> bysort race : gen id = _n
>
> or
>
> bysort race : egen id = seq()
>
> although note that the labelling produced is essentially arbitrary
> in either case.
>
> Nick
> [email protected]
>
> [email protected]
>
> > for example, there are 17 people who have the same ethnicity.
> > If I want to give
> > them a sequential number 1 2 3..........17, how can I use lag
> > function to do this?
>
> *
> * For searches and help try:
> * http://www.stata.com/support/faqs/res/findit.html
> * http://www.stata.com/support/statalist/faq
> * http://www.ats.ucla.edu/stat/stata/
>
*
* For searches and help try:
* http://www.stata.com/support/faqs/res/findit.html
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/