To remove leading zeros from the string variable x without looping, how
about:
replace x=substr(x, indexnot(x, "0"), . )
Jamie Griffin
>>> [email protected] 09/06/05 7:27 pm >>>
This is not really a splitting problem,
at least not sensu -split-.
To remove leading zeros, I would do this:
quietly {
count if substr(myvar,1,1) == "0"
while `r(N)' {
replace myvar = substr(myvar,2,.) ///
if substr(myvar,1,1) == "0"
count if substr(myvar,1,1) == "0"
}
}
Any solutions without looping?
Nick
[email protected]
>>> Raphael Fraser
I have a string variable of the type listed below:
id
0008
0020
016A
0160C
How do I remove the leading zeros from this variable? I tried using
the -split- command, but it removed both leading and trailing zeros.
The end result should look like this:
id
8
20
16A
160C
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