Re: st: quantile regression question

["Antonio Fanari" <afanar@hotmail.com>]

Thanks!
Tony

> From: Robert Duval <rduval@gmail.com>
> Reply-To: statalist@hsphsun2.harvard.edu
> To: statalist@hsphsun2.harvard.edu
> Subject: Re: st: quantile regression question
> Date: Mon, 25 Jul 2005 22:56:58 -0400
>
> quantile regression fits a line at different points of the CONDITIONAL
> distribution of y given x, i.e.  f(y|x).
>
>  At each fixed value of x (i.e. x=x0) f(y|x=x0) gives you the
> distribution of y after controlling for x (a distribution of the
> errors in other words). Qreg fits a line at a given (prespecifed)
> quantile of such distribution.
>
> If you're not including variable z as a regressor in the conditioning
> set then qreg won't give you what you want as stated in your goal (
> "coefficients of experience in a series of  wage regressions by
> quantile of the distribuiton of ability").
>
> If you're willing to assume exogeneity on your excluded variable z, it
> seems to me that it would suffice to just split the sample by
> quantiles of the excluded variable and run an ordinary regression over
> each sample (a fully interactive model in other words).
>
> robert
>
>
> On 7/25/05, Antonio Fanari <afanar@hotmail.com> wrote:
> > Hi,
> > is it possible to run quantile regressions where the quantiles are not
> > defined over the independent variable but over some other variable?
> > Say you have wages as a dependent variable and another variable 
> measuring
> > ability (e.g. an IQ test). Suppose you want to see if the effect of, 
> say,
> > experience on wages varies across quantiles of ability. One way is to
> > include interactions of experience*ability in a traditional OLS 
> regression.
> > However, I was wondering if there is a way to run quantile regressions,
> > instead. So one would come up with coefficients of experience in a 
> series of
> > wage regressions by quantile of the distribuiton of ability.
> > Please forgive me if the question does not make any sense, but I would
> > appreciate any feedback!
> > Thanks.
> > Tony Fanari
> >
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