I don't know if this is useful or more for the sake of
completeness but I tend to go down the (equivalent)
route suggested by Eric at the end of his original
message - just parse out all time and date information
from the original string variable and perhaps do:
. egen double tstp=dhms(edate hr min sec)
which, as far as I understand, is the same as:
. g double tstp = edate + (hr + min/60 + sec/3600)/24
Alternatively, Bill Gould once suggested to create a
variable containing the number of seconds since
01jan1960 00:00:00:
. gen double esecs = date*24*60*60 + hour*60*60 +
min*60 + sec
Best wishes,
Sylvain
--- David Harrison <[email protected]> wrote:
> As an alternative to Joseph's ODBC suggestion... If
> you have StatTransfer, then you can bring the data
> into Stata with -inputst- and this will bring the
> date/time field in as a numeric daily date with a
> fractional part representing the time.
>
> For example 6pm today would be 16602.75
>
> The only problem with this is that Stata has no
> date/time display format, so with %d display format
> this would just show "15jun2005".
>
> David
>
> -----Original Message-----
> From: Eric G. Wruck [mailto:[email protected]]
> Sent: 15 June 2005 14:41
> Subject: st: Date + Time of Day
>
>
> I have an Excel spreadsheet which includes a date
> column & dates are
> in the following form:
>
> 11/14/2000 16:27:00
>
> That is, the date includes the time of day. I've
> searched my Stata 9
> manuals & all I can find on time is part of
> c(return) where one can
> use c(current_time) but this doesn't seem
> relevant/helpful.
>
> Is there a format that includes time as part of a
> date, or do I have
> to parse this field out & create my own separate
> time variable? What
> do others do to handle this?
>
> Thanks,
>
> Eric
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