Aaaaah, I need coffee, and lots of it:
if:
L(xb)= exp(xb)/(1+exp(xb))
then:
dL/d(xb)=exp(xb)/(1+exp(xb))^2
not:
dL/d(xb)=exp(xb)/(1+xb)^2
--- In [email protected], "maartenbuis" <maartenbuis@y...>
wrote:
> Oops, the explanation in
http://www.stata.com/statalist/archive/2004-
> 11/msg00264.html contains a typo. The commands are correct though.
>
> if:
> L(xb)= exp(xb)/(1-exp(xb))
>
> then:
> dL/d(xb)=exp(xb)/(1-exp(xb))^2
>
> not:
> dL/d(xb)=exp(xb)/(1-xb)^2
>
>
>
>
> *
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*
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