The Stata solution is immaterial here. Providing
code avoids the issue of whether the results
are of any statistical or scientific use.
Nick
[email protected]
Rijo John
> One simple solution would be, I think, to use the egen
> command with the
> max option. for example
>
> egen maxval=max(mf) if temp==26, by(time)
> This will generate a new variable with the max of mf. then
> may be you can
> give a count command (again using egen) and get the percentages.....
>
> Nevertheless there may be easier ways to do this also....
Syed O Masood
> :I have put a piece of data below.
> :I need to find what percent of people have maximum
> :value in the variable rf at time 1 and temp 26, what
> :percent of people will have maximum value of mf at
> :time 2 and temp 26, what percent of people have max
> :value of mf at time 3 and temp 26 and similarly for
> :tmep 35oC.
> :
> :Thanks in advance for your help & support
> :
> :. list temp time mf
> :
> : +---------------------+
> : | temp time mf |
> : |---------------------|
> : 1. | 26 1 5.5 |
> : 2. | 26 2 8.64 |
>
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