After this syntax, what is specified
in -preffect()- will be visible as `preffect'.
This will be a string (emphatically not
a string variable). The ` ' are essential.
di preffect
by itself will be interpreted as
a reference to a variable -preffect-,
in fact to -preffect[1]-, which evidently
you don't have.
If you don't have anything compulsory before
the options the syntax should be
syntax [, PREffect(string)]
Nick
[email protected]
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]]On Behalf Of
> DOMINIC MUSTON
> Sent: 18 May 2004 19:32
> To: [email protected]
> Subject: st: Syntax syntax
>
>
> I'm pulling my hair out with this problem - I just can't see what's
> wrong, so any help much appreciated! The problem I'm having contains
> syntax for the "syntax" programming command.
>
> A program I'm writing includes the line:
>
> syntax [anything] [, PREffect(string)]
>
> This is intended to pick-up an optional option called "preffect" (or
> "pre" for short) with the contents of the brackets recorded
> as a string
> variable.
>
> The next line of my program is:
>
> display preffect
>
> Yet when I run the program specifying the preffect option (including
> something in brackets), the "display" command displays nothing - it
> appears that the contents of the bracket following the preffect option
> in the command line have not been picked-up.
>
> Why not? How can I get my program to pick-up the contents of the
> option?
>
> (What's the [anything] code about? Without it, I get a "varlist not
> allowed" error. I guess putting [anything] in the program is not great
> practice, but I would like to get the options problem sorted out
> first.)
>
> Thank you very much!
>
> Dominic Muston.
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>
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