A gradient of .3 doesn't give you a 30 degree line.
Setting aside any question of aspect ratio, a gradient
of .3 corresponds to about 17 degrees.
Nick
[email protected]
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]]On Behalf Of Dimitriy V.
> Masterov
> Sent: 07 March 2004 16:35
> To: [email protected]
> Subject: Re: st: superimpose 45 degree line in -scatter-
>
>
>
>
> For adding lines, my quick and dirty solution is to plot x
> against x and
> not label the line, using twoway command. This will give you
> a 45 line.
> You can define some variables to give you any slope you want.
> For example,
> if you wanted a 30 line.
>
> gen h=_n;
> gen v=.3*x;
>
> Here is the command:
>
> twoway (scatter y x, sort) (line v x), legend(off);
>
> Perhaps there is a more elegant way.
>
> DVM
>
>
> On Sun, 7 Mar 2004 [email protected] wrote:
>
> > Dear Statalisters,
> >
> > I'm using Stata 8 and I would like to know whether and how
> it is possible to
> > superimpose a 45 degree line, a 30 degree line, etc over a
> -scatter- graph.
> >
> > Further, does Stata support graphs in polar coordinate
> planes? Or did someone
> > wrote something on this?
> >
> > many thanks in advance,
> > Dimitris Christodoulou
> >
> > --
> > This mail sent through http://webmail.bangor.ac.uk
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> >
>
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>
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