As ever many thanks for your assistance. For each value of code there are 7
values of id and I was attempting to produce an output listing the integral,
id and associated code.
Martyn
Youth Rugby: www.fullerians.demon.co.uk
"The difference between winners and losers is that winners tell the jokes
and the losers talk about the run of the ball."
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Nick Cox
Sent: 12 August 2003 11:41
To: [email protected]
Subject: st: RE: Re: Programming help
Dr. Martyn Sherriff
> This loops correctly over i, but in the data set the
> variable code takes the
> values 96,137(1). I need to print out the code for
> reference only but it
> does not change from the initial value if 96. What should I
> do to modify the
> program? Can I write the "displayed" variables directly to
> an output file?
>
> set more off
> forvalues i=1/294{
> integ volume rtime if id==`i', gen(Sv)
> display code `i' " r(integral)
> drop Sv
> }
> set more on
I am not sure I understand what you want but
. display code `i'
will always be interpreted as if you
were saying
. display code[1] `i'
In essence, the -display- statement has no
way of knowing that you consider a particular
value of -code- to be the current value. -display-
arbitrarily choose the first value of a variable
if none is specified.
What's more, there will be no
space between the two items printed.
It sounds as if you want something more
like
forval i = 1/294 {
qui integ volume rtime if id == `i'
display code[`i'] " " r(integral)
}
where I have omitted generating an optional
variable only to -drop- it a moment later.
If you shut up -integ-, you can just
collate the results within a log. There
are other ways to do it, e.g. -file-.
Nick
[email protected]
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