Re: st: RE: stat question re.: z

["b. water" <barleywater@hotmail.com>]

Thank you to Ted and Alan for their replies. Alan was spot on, I found 
'invnorm' and read more about it using help invnorm in Stata.

Alan, this expression was part of the equation for working out sample size 
for comparative studies in medical testing. I located Z the old fashion way 
by looking up textbook table but since I am a Stata user, thought I should 
learn how to do it in Stata.

Cheers,
bw



> From: "FEIVESON, ALAN H. (AL) (JSC-SK) (NASA)" <alan.h.feiveson@nasa.gov>
> Reply-To: statalist@hsphsun2.harvard.edu
> To: "'statalist@hsphsun2.harvard.edu'" <statalist@hsphsun2.harvard.edu>
> Subject: st: RE: stat question re.: z
> Date: Thu, 19 Jun 2003 15:28:16 -0500
>
> bw - I think what you mean is ((invnorm(0.9) + invnorm(0.975))/log(1.2))^2
>
> but what is this supposed to give you?
>
>
>
>
>
> Al Feiveson
>
>
> -----Original Message-----
> From: b. water [mailto:barleywater@hotmail.com]
> Sent: Thursday, June 19, 2003 1:25 PM
> To: statalist@hsphsun2.harvard.edu
> Subject: st: stat question re.: z
>
>
> dear all,
>
> i would appreciate help and advise on this matter. i want to calculate
> ((Z^0.9 + Z^0.975)/log 1.2)^2. how can i do this in stata? i tried to 
> search
>
> stata and references for usage of Z but no such luck. thank you all for 
> your
>
> advise and help.
>
> kind regards,
> bw
>
> ps: sorry if this reveals my ignorance
>
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