Nick has correctly guessed the Stata idiom for converting most of the
illustrated SAS programming constructs. One problem, however, is that SAS
allows variable arrays and I believe these still do not exist in Stata. You
can program around this, of course, but that's not a simple matter of
converting from one language to another. Those with Stata 7 will benefit
from the "new" looping commands. Those of us who still can't afford to
upgrade must resort to -while- loops.
-----Original Message-----
From: [email protected]
[mailto:[email protected]]On Behalf Of Nick Cox
Sent: Tuesday, November 19, 2002 5:40 AM
To: [email protected]
Subject: st: RE: syntax question
[email protected]
>
> Hi Stata users, I'm now trying to convert SAS language to
> Stata. Since I'm relatively new to Stata, any help will be
> greatly appreciated!!!!
>
> The SAS language I try to rewrite for Stata is
>
> do i =1 to 6;
>
> if (ICAT EQ i) then do;
>
> do j =1 to 4;
>
> if (KiAj{j,1} > 0) and (KiGj{j,1} > 0) then do;
> IGC{i} =IGC{i} + KiGj{j,1};
> IGC_h{i} =IGC_h{i} + KiAj{j,1};
> IHC{i} =IHC{i} + KiHj{j,1};
> end;
>
What is SAS? Or more seriously, I don't know SAS,
so I am guessing.
do seems to map to -forvalues-. There is a tutorial
on -forvalues- -- for which you need to know the
rudiments of local macros -- at
http://www.stata.com/support/meeting/8uk/fortitude.pdf
EQ presumably is a test for equality so that is ==.
The main pitfall to be aware is the difference in Stata
between the -if- command and the -if- qualifier.
See http://www.stata.com/support/faqs/lang/ifqualifier.html
Nick
[email protected]
*
* For searches and help try:
* http://www.stata.com/support/faqs/res/findit.html
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
*
* For searches and help try:
* http://www.stata.com/support/faqs/res/findit.html
* http://www.stata.com/support/statalist/faq
* http://www.ats.ucla.edu/stat/stata/
